Solve the differential equation by variation of parameters. y'' + y = csc x Your solution’s ready to go! Our expert help has broken down your problem into an easy-to-learn solution you can count on.

y ″ + y = csc ⁡ (x) The solution to the above non-homogeneous equation is given by: View the full ...

Question 1167385: Solve the differential equation: y’ = csc x - y cot x * Answer by solver91311(24713) ( Show Source ): You can put this solution on YOUR website!

Question: Consider the following differential equation to be solved by variation of parameters. y + y = csc(x) Find the complementary function of the differential equation. Find the general solution of the differential equation. Y(x) = Consider the following differential equation to be solved by variation of parameters.

Solve the differential equation by variation of parameters. y" + y = csc(x) y(x) = cos(x) + C sin(x) – cos(x) + log(sin(x))sin(x) X Solve the given system of differential equations by systematic elimination. 20+ dy et dt dx dt 4x + dt dy dt X + 4et (-19, ve) - …

Question 6 Find the derivative. y = (csc x + cot x)(CSC X - cot x) O y'= - CSC X cot x O y'= 1 O y'= 0 O y'= - CSC2 x Question 7 Find the derivative of the function. q = V12r - 15 1 2012r - 15 o 12-514 2V12r - 15 -5r4 V12r-15 1 2V12-5r4 Question 8 Find dy/dt. y = t2(t + 225 O 9t®(+4 + 2)4(20+4 + 2) Otºtº + 2)^(2913 +18) 180t34(+4 + 2)4 O t8(+4 + 2)4(29+4 + 18) Question 9 Find the derivative ...

Question: Consider the following differential equation to be solved by variation of parameters. y'' + y = csc(x) Find the complementary function of the differential equation. yc(x) = Find the general solution of the differential equation. y(x) =

Answer to Consider the following differential equation to be. Math; Calculus; Calculus questions and answers; Consider the following differential equation to be solved by variation of parameters. y′′+y=csc(x) Find the complementary function of the differential equation. yC(x)=C1cos(x)+C2sin(x) Find the general solution of the differential equation. y(x)=C1cos(x)+C2sin(x)−xcos(x)sin(x)log ...

Question: Proceed as in Example 3 of Section 4.8 to find a solution of the given initial-value problem. Evaluate the integral that defines y_p(x). y" + y = csc x cot x, y(pi/2) = 0, y'(pi/2) = 0 y_p (x) =

Jul 22, 2015 · Period of y = csc (x - pi/2) Ans: 2pi y = 1/sin (x - pi/2) The period of sin x is 2pi, then the period of y is also 2pi.