
SOLUTION: graph xy=12 - Algebra Homework Help
Click here to see ALL problems on Equations; Question 415974: graph xy=12 Answer by MathLover1(20820) (Show Source): . You can put this solution on YOUR website! graph
SOLUTION: xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2
You can put this solution on YOUR website! xy=12, (x^2+y^2)=25 then what is the value of (x+y)2^2; Observing , it's obvious that x and y MUST be 3 and 4
SOLUTION: x2+y2=25 xy=12 - Algebra Homework Help
You can put this solution on YOUR website! x2+y2=25 xy=12-----Solve the 2nd equation for y and substitute into the 1st equation.
SOLUTION: I need help making a coordinate table for this …
Question 251286: I need help making a coordinate table for this equation: xy = 12 Answer by checkley77(12844) ( Show Source ): You can put this solution on YOUR website!
XY=12, YZ=2x, And XZ=28 - Algebra Homework Help
XY=12, YZ=2x, And XZ=28 Answer by fcabanski(1391) (Show Source): You can put this solution on YOUR website!
SOLUTION: x+y=6 x-y=12 - Algebra Homework Help
You can put this solution on YOUR website! x+y=6 x-y=12 solve the second eqution for x x=12+y substitute 12+y in for x in the first equation
SOLUTION: The equation of a curve xy = 12 and the equation of a …
Question 1200186: The equation of a curve xy = 12 and the equation of a line L is 2x + y = k, where k is a constant. i) In the case where k = 11, find the coordinates of the points of intersction of L and the curve. ii) Find the set of values of & for which I does not intersect the curve. Answer by math_tutor2020(3796) (Show Source):
SOLUTION: xy = –12. What is the constant of variation for this ...
Question 842681: xy = –12. What is the constant of variation for this relationship? What is the constant of variation for this relationship? Answer by ewatrrr(24785) ( Show Source ):
SOLUTION: Please help me solve the substituation x+y=12 and x …
Algebra -> Coordinate Systems and Linear Equations -> SOLUTION: Please help me solve the substituation x+y=12 and x-y=-4.
SOLUTION: If x^2 + y^2 = 40 and xy = 12, then x + y = A. 7. B. 8.
You can put this solution on YOUR website! x^2 + y^2 = 40 xy = 12 or x=12/y Now replace x in the first equation with 12/y & solve for y.