Divide each term in 2x = π 4 2 x = π 4 by 2 2 and simplify. Tap for more steps... The tangent function is positive in the first and third quadrants. To find the second solution, add the reference angle from π π to find the solution in the fourth quadrant. 2x = π + π 4 2 x = π + π 4. Solve for x x. Tap for more steps...

What is the general solution for tan (2x)=1 ?

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use that \tan(2x)=\frac{2\tan(x))}{1-\tan(x)^2} and \tan(x)=\frac{\sin(x)}{\cos(x)}

Enter a problem... Graph each side of the equation. The solution is the x-value of the point of intersection. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor.

prove\:\cot(2x)=\frac{1-\tan^2(x)}{2\tan(x)} prove\:\csc(2x)=\frac{\sec(x)}{2\sin(x)} prove\:\frac{\sin(3x)+\sin(7x)}{\cos(3x)-\cos(7x)}=\cot(2x)

The formula for tan^2x are: tan^2x = sec^2x - 1 ⇒ tan 2 x = sec 2 x - 1; tan^2x = sin^2x / cos^2x ⇒ tan 2 x = sin 2 x/cos 2 x; tan^2x = 1/cot^2x ⇒ tan 2 x = 1/cot 2 x; What is the Difference Between tan2x and tan^2x? Tan2x is a double angle trigonometric formula which gives the value of the tangent function for the compound angle 2x.

Jun 28, 2019 · $$\tan(2x)=\tan\left(\frac\pi2-x\right)\iff 2x=\frac\pi2-x+k\pi\iff x=\frac{1+2k}{6}\pi$$ and every step is justified. But the domain of the LHS excludes $$x=\frac{1+2k}{2}\pi$$ and these solutions must be rejected.

Find the general solution for each of the following equations sec 2 2x = 1– tan 2x. Find the general solution of the equation sin x + sin 3x + sin 5x = 0. If \[\tan x = \frac{b}{a}\] , then find the values of \[\sqrt{\frac{a + b}{a - b}} + \sqrt{\frac{a - b}{a + b}}\]. If \[T_n = \sin^n x + \cos^n x\], prove that \[2 T_6 - 3 T_4 + 1 = 0\]

tan(x y) = (tan x tan y) / (1 tan x tan y) sin(2x) = 2 sin x cos x cos(2x) = cos ^2 (x) - sin ^2 (x) = 2 cos ^2 (x) - 1 = 1 - 2 sin ^2 (x)