Definition of $L^\\infty$ - Mathematics Stack Exchange
Jan 8, 2017 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …
functional analysis - Elements of Sequence Space $l^\infty ...
I'm studying functional analysis, specifically metric space section using Kreyzig's Introductory Functional Analysis with Application textbook.
Can we identify the duals of $\\ell^\\infty$ and $L^{\\infty}$ with ...
Yes, if $(\Omega, \Sigma, \mu)$ is a (complete) $\sigma$-finite measure space then $(L^{\infty}(\Omega,\Sigma,\mu))^{\ast}$ is the space $\operatorname{ba}(\Omega, …
real analysis - Prove that the normed space $L^{\infty}$ equipped …
$\begingroup$ Ok, well I thought L^infinity was the completion of l^infinity in the same way that L^2 is the completion of l^2. And the notation is not that confusing for me because I am used …
Why is $L^{\\infty}$ not separable? - Mathematics Stack Exchange
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Dual of $l^\\infty$ is not $l^1$ - Mathematics Stack Exchange
Jul 16, 2014 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for …
Proving that $l_\\infty$ is complete - Mathematics Stack Exchange
Apr 12, 2019 · I'm learning about Hilbert spaces and operators theory, from some book. I came across the following question - And the books' answer: What I don't understand in the proof - …
real analysis - Why is $\ell^\infty(\mathbb{N})$ not separable ...
Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …
Why are continuous functions not dense in $L^\\infty$?
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Closed subspace of $l^\\infty$ - Mathematics Stack Exchange
Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their …