Apr 19, 2015 · There exists 4 trigonometric quadrants. All, Sine, Tan & Cos . 570 degrees turns out to land in the tan quadrant, therefore cos(570) has to be negative. 90 (all) + 90 (sin) + 90 (tan) + 90 (cos) + 90 (all) + 90 (sin) + 30 (tan) makes 570 degrees and the last turn helps us land in the tan quadrant. Remember that 90+90+90+90+90+90+30=570. So we have to create a 30 …

May 7, 2018 · How do you solve this? Solve the equation for exact solutions in the interval [0degrees ,360degrees ). Use an algebraic m

What is the exact value of #cot 210#? What is the exact value of #sec 60#? ...

Jun 15, 2018 · How do you find the value of #cot 300^@#? What is the value of #sin -45^@#? How do you find the trigonometric functions of values that are greater than #360^@#?

Apr 15, 2018 · Use these two trig identities: #cottheta=costheta/sintheta# #sectheta=1/costheta# And the Pythagorean identity (and its variations):

Jun 21, 2017 · How do you find the exact value of #cot^-1(cot((2pi)/3))#? Trigonometry Inverse Trigonometric Functions Basic Inverse Trigonometric Functions

May 5, 2015 · cot 240 = cot ( 60 + 180) = cot 60 = (sqr3)/3

Feb 22, 2018 · cos x tan x = cos x \\frac{sin x}{cos x} = sin x = 1/2 The sine of 30 degrees is 1/2. Also, at 150 degrees. Realizing that the tangent function is the ratio of sine and cosine makes the problem much easier. Between 0 and 360 degrees there are two points where the sin is 1/2: 30, 150. The sine function is equal to -1/2 at 210, and 330 degrees.

Apr 16, 2015 · If tan(x) is negative and sin(x) is positive, x must be in Quadrant 2 and evaluation is only a matter of reading the graph. Assuming x epsilon [0,2pi] sin(x) = 2/sqrt(85) cos(x) = - 9/sqrt(85) csc(x) = sqrt(85)/2 sec(x) = -sqrt(85)/9 cot(x) = -9/2#

May 5, 2016 · Use Properties: #cos(A-B)=cosAcosB+sinAsinB# #sin(A-B)=sin A cos B-cos A sin B#. Left Side: #=sec^2x-cot^2(pi/2 -x)#