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  1. How do you use logarithmic differentiation to find the derivative of

    Mar 17, 2018 · #y=(cosx)^x# take natural logs of bothe sides. #lny=ln(cosx)^x# #=>lny=xlncosx# now differentite #wrt" "x#. the #RHS will need the product rule

  2. How do you differentiate #f(x) = log(log x)#? - Socratic

    What is the derivative of #f(x)=(log_6(x))^2# ? See all questions in Differentiating Logarithmic Functions without Base e Impact of this question

  3. How do I evaluate the integral #int(secx tanx) / (sec^2(x ... - Socratic

    Jan 26, 2015 · Substituting back y=t-1, one has \log(t-1)+c, and again, plugging t=\cos(x) into the equation, one has ...

  4. Express Log(Log(cosπ+isinπ)in the form of A+iB? - Socratic

    May 31, 2018 · A=lnpi B=pi"/"2+2npi where n is an integer. Instead of a vague log, let's use the natural logarithm so things simplify nicely. We have a complex number z=lnln(color(red)(cospi+isinpi)) for which we want to find the real part, A and the imaginary part,B respectively. What we have inside of the composed ln function resembles Euler's identity, which states that e^(icolor(blue)x)=coscolor(blue)x ...

  5. How do you find the general solutions for cos 2x + cos x - 2 =0?

    Aug 12, 2015 · How do you find the general solutions for #cos 2x + cos x - 2 =0#? Trigonometry Trigonometric Identities and Equations Solving Trigonometric Equations

  6. What is the derivative of #y=(lnx)^(cosx)#? - Socratic

    Mar 7, 2017 · What is the derivative of #y=(lnx)^(cosx)#? Calculus Differentiating Logarithmic Functions Differentiating Logarithmic Functions without Base e

  7. How do you differentiate #log_2 (e)#? - Socratic

    Mar 16, 2016 · This is a constant. The derivative of any constant, with respect to any variable, is 0. log_a a = 1, log_e e = (log_2 e) (log_e 2). So, log_2 e = 1/log_e 2 = 1/ln 2 = 1.4427, nearly. .

  8. What is the domain and range for #y = xcos^-1[x]#? - Socratic

    Jul 28, 2018 · Range: [ - pi, 0.56109634 ], nearly. Domain: { - 1, 1 ]. arccos x = y/x in [ 0, pi ] rArr polar theta in [ 0, arctan pi ] and [ pi + arctan pi, 3/2pi ] y' = arccos x - x / sqrt( 1 - x^2 ) = 0, at x = X = 0.65, nearly, from graph. y'' < 0, x > 0. So, max y = X arccos X = 0.56, nearly Note that the terminal on the x-axis is [ 0, 1 ]. Inversely, x = cos ( y/x ) in [ -1, 1 } At the lower terminal ...

  9. How do you find the derivative of #y = log (x^2 + 1)#? - Socratic

    Mar 3, 2016 · What is the derivative of #f(x)=(log_6(x))^2# ? See all questions in Differentiating Logarithmic Functions without Base e Impact of this question

  10. What is the derivative of #log_2(3x-1)#? - Socratic

    Sep 10, 2015 · d/dx log_2(3x-1) = 3/(3xln 2-ln2) You might already know that: d/dx ln x = 1/x In order to use this, we have to apply the change of base rule: log_a(b) = log_c(b)/log_c(a) Therefore: log_2(3x-1) = ln (3x-1)/ ln 2 Now we can differentiate the expression: d/dx ln (3x-1)/ ln 2 1/ln 2 is a constant, so we can bring it out: d/dx ln (3x-1)/ ln 2 = 1/ln 2 * d/dx ln (3x-1) Next, we can use the chain ...