We need. #intsecxdx=int((secx(tanx+secx)dx)/(tanx+secx))# #=int((secxtanx+sec^2x)dx)/(tanx+secx)# Let #u=tanx+secx#, #=>#, #du=(sec^2x+secxtanx)dx#

Jul 30, 2018 · We know that , #color(red)((1)(a-b)(a^2+ab+b^2)=a^3-b^3# #color(blue)((2)tan(A-B)=(tanA-tanB)/(1+tanAtanB)# #color(brown)((3)lim_(theta to0)(tantheta)/(theta)=1#

Apr 6, 2018 · #LHS=tan(x+(3pi)/4)# #=(tanx+tan((3pi)/4))/(1-tanxtan((3pi)/4))# #=(tanx+tan(pi-pi/4))/(1-tanxtan(pi-pi/4))# ...

Mar 29, 2018 · #tanx/(1-cotx)+cotx/(1-tanx)#, #=(sinx/cosx)/(1-cosx/sinx)+(cosx/sinx)/(1-sinx/cosx)#, #={sinx/cosx-:(sinx-cosx)/sinx}+{cosx/sinx-:(cosx-sinx)/cosx}#,

Nov 7, 2015 · f'(tanx)=sec^2x Using the trig identities, recall that tanx can be rewritten as sinx/cosx. Now differentiate using quotient rule: d/dx(f(x)/g(x)) = (g(x)*f'(x) - f(x)*g'(x))/g(x)^2 …

graph{tan x [-10, 10, -5, 5]}. See explanation. graph{tan x [-10, 10, -5, 5]} The number of lines you have to draw depends on the domain provided. If the domain is not specifically provided, you …

May 10, 2018 · How do you evaluate the integral #(secx tanx) / (sec^2(x) - secx)# dx? Calculus Techniques of Integration Integration by Trigonometric Substitution 1 Answer

Aug 23, 2017 · but as #tanx# is positive, #sinx# and #cosx# would be positive and negative together. Answer link.

Feb 23, 2016 · It is not an identity. It cannot be verified. The left side is not always equal to the right. For example at x=pi/6 the left side is 4 and the right side is (4sqrt3)/3

Mar 13, 2018 · What is the derivative of #f(x) = sin (cos (tanx) )#? Calculus Basic Differentiation Rules Chain Rule. 1 Answer