Feb 2, 2016 · sin(x+pi)=-sin(x)=sin(-x)=cos(pi/2 +x) cos (x+pi)=-cos(x) So According to the question cos(pi/2 +x)=cos(x) Using solution of cos we get (pi/2) + x = 2npi +- (x) So case I:- (pi/2) + x = 2npi + (x) But here, the value of x is cancelled, so case II:- (pi/2) + x = 2npi - (x) x=npi-pi/4 The solution of this equation is x=npi-pi/4

May 18, 2018 · Calculus Differentiating Trigonometric Functions Differentiating sin(x) from First Principles. 1 Answer . Nam D.

Apr 7, 2016 · 0, pi, (2pi)/3, (4pi)/3, 2pi sin 2x + sin x = 0 Apply the identity: sin 2x = 2sin x.cos x 2sin x.cos x + sin x = 0. sin x(2cos x + 1) = 0 a. sin x = 0 --> x = 0, x = pi and x = 2pi b/ 2cos x + 1 = 0 cos x = -1/2 --> x = +- (2pi)/3 Answers for (0, 2pi): 0, pi, (2pi)/3, (4pi)/3, 2pi Reminder arc (4pi)/3 is co-terminal to arc -(2pi)/3

Aug 17, 2015 · dy/dx = (y [cos (xy) + sin x])/(cos x - x cos (xy)) Always think of your chain, product and quotient rules when differentiating y cos x = 1 + sin (xy) Diff wrt x: dy ...

Feb 12, 2017 · How do you find the domain and range of # arcsin(sin x)#? Trigonometry Inverse Trigonometric Functions Inverse Trigonometric Properties. 1 Answer

Dec 28, 2016 · How do you solve for x in #3sin2x=cos2x# for the interval #0 ≤ x < 2π# See all questions in Solving Trigonometric Equations Impact of this question

Feb 29, 2016 · 0, pi/4, pi/2, (3pi)/4, (5pi)/4, (3pi)/2, (7pi)/4 and 2pi Call x/2 = t . Apply the identity: sin 2a = 2sin a.cos a (sin t)/(cos t) - 2sin t.cos t = 0.

Oct 18, 2015 · Use calculator. sin x = 0.723 --> arc #x = 46^@30#. Trig unit circle gives another arc x that has the same sin value -->

Aug 6, 2016 · #int (1+cos^2(x)) / sin(x) dx# is just crying out for the application of the Pythagorean identity #=int (1+ color(red)(1 - sin^2 x)) / sin(x) dx#

Mar 12, 2016 · Horizontal asymptote: y=0 Vertical asymptotes: x=-9 x=9 When we factorize the denominator, we can write f(x) = frac{sin(x)}{(x+9)x(x-9) For this kind of function, we have to check for the points where the denominator is zero, as there cannot be division by zero. Also we need to check for +- oo. Since the numerator fluctuates about -1 to 1, while the denominator keeps increasing in magnitude ...