Apr 16, 2016 · We have 2 mol of sodium metal to start; clearly we need the 1 mole of Cl_2(g). "Moles of sodium "=(46.0*g)/(22.9*g*mol^-1)=2*mol. Given your equation, clearly we need the ONE mole of Cl_2 gas. What is the mass of this quantity of chlorine? It is fact that all of the elemental gases EXCEPT for the Noble Gases are diatomic: N_2, O_2, F_2, Cl_2. Of course, all the halogens, as the elements, are ...

Nov 23, 2017 · So, pick one reactant and use the mole ratio that exists between the two reactants to see what you can find. 6.7 color(red)(cancel(color(black)("moles Na"))) * "1 mole Cl"_2/(color(blue)(2)color(red)(cancel(color(black)("moles Na")))) = "3.35 moles Cl"_2 This means that in order for all the moles of sodium to react, you must provide 3.35 moles ...

A chemist performs the synthesis of sodium chloride from its elements. The chemist begins with 46 grams of sodium. How many moles of chlorine are needed? 2 Na + Cl2 → 2 NaCl What mass of calcium chromate is formed when 35 grams of calcium nitrate reacts with sodium carbonate? Question #975d6

Dec 3, 2016 · Na(s)+1/2Cl_2(g) rarrNaCl(s) "Moles of NaCl" = (26.0*g)/(58.44*g*mol^-1)=0.445*mol. And thus we need half an equiv of Cl_2 gas, i.e. 0.222*mol. If we use the Ideal Gas law, then V=(nRT)/P, and also we know that 760*mm*Hg-=1*atm.

Mar 1, 2018 · "7.1 g" Chemical formula of sodium chloride is NaCl Molar mass :58.5g Molar mass of sodium :23g Molar mass of chlorine :35.5g Mass of NaCl we have is 18g Recall n=m/M (where n is number of moles, m is given mass, M is molar mass) n=18/58.5 Now using this for sodium 18/58.5=m/23 m= "7.1 g"

Jan 11, 2018 · Consider, Cl_2 + 2NaI to 2NaCl + I_2 having two half reactions, one reduction and one oxidation, in turn, Cl_2 rightleftharpoons 2Cl^(-), and 2I^(-) rightleftharpoons I_2 To be sure, the chlorine diatomic molecule is being reduced into two chloride ions that ionically bond with the sodium ions left over from the iodide ions being oxidized. The source of electrons are the iodide ions, which go ...

Apr 23, 2014 · Let us begin with a very basic chemical reaction between nitrogen and hydrogen to create ammonia The reaction is N_2 + H_2 -> NH_3 The first step is to take an atom inventory of both sides of the equation. Reactants N = 2 H = 2 Products N = 1 H = 3 To balance the unbalanced atoms of nitrogen we add a coefficient of 2 in front of the ammonia on the product side. N_2 + H_2 -> 2NH_3 This changes ...

May 27, 2018 · It is sodium chloride, "NaCl", which is common table salt. Balanced equation "2Na(s) + Cl"_2("g")"rarr"2NaCl(s

Jan 9, 2018 · Since there is only one reactant, so it appears as if the decomposition of sodium chloride is the reaction. "2NaCl(l)""rarr"2Na(s)" + "Cl"_2("g")" At first, the sodium metal is in its molten state. It does seem to indicate that the only reactant is sodium chloride, which would also seem to indicate a decomposition reaction. "2NaCl(l)""rarr"2Na(s)" + "Cl"_2("g")" In order for the decomposition ...

May 26, 2018 · Well, you define "STP" first....I get approx. 30*L According to the site, "STP" specifies a temperature of 273.15*K, and a pressure of 100*kPa...