Dec 6, 2007 · ln x^2 = 2lnx (lnx)^2 = (ln x)*(lnx) so no they are not equal (there may be a value for which they are but ...

Jan 16, 2010 · u= ln(x2+y2) is a harmonic function find a harmonic conjugate function v and the analytic function f(z) ? S.

Jan 15, 2009 · Find the intervals on which f(x) = ln(x² + 1) is concave up I got critical points to be -1, and 1 I checked by the first derivative that from - infinity to 0 the slope is negative and from …

Jun 9, 2010 · Hey, perhaps the numerator \ln{x}^2 instead of \ln^2(x), which is little easier and probably more common? In any case, it can't get clearer than Tom's posts, so try to follow …

Sep 24, 2008 · 3. "Find an expression for the sum of the first 35 terms of the series ln x^2 + ln x^2/y + ln x^2/y^2 + ln x^2/y^3 + ln x^2/y^4. Giving your answer in the form ln x^m/y^n, where …

Feb 28, 2011 · Another one I'm currently stuck on: "Let f(x,y)=x^2+ln(y). Find the average rate of change of f as you go from (3,1) to (1,2). Find the instantaneous rate of change of f as you …

Feb 9, 2010 · \int \frac{1}{1+u} du = ln(1 + u) + C I know I can integrate the terms of the geometric series to get the natural log, but I also know I can't just plug u = a^3 - x^3 - 1 , and now I'm not …

Nov 10, 2008 · The exact equation I was trying to solve was 2^x = x^2, which equates to ln(x) / x = ln(2)/2, and rearranging for the W function, you get -x ln(2) / 2 = W[-ln(2) / 2] = -ln(2), so x=2. …

Mar 29, 2009 · now, my lecturer defined 'strictly increasing' as 'if x1 < x2, f(x1) < f(x2)'. now in order to find where a function is strictly increasing, i find the derivative and find for what …

Apr 30, 2018 · Question: Consider the function \\frac{2x}{1+x^2}. What is the radius of convergence for the Maclaurin Series approximating this function? My thoughts: I can take the …