Mar 13, 2021 · In reaction of $\ce{KMnO4}$ with $\ce{I-}$ in acidic medium $\ce{I2}$ will be formed, whereas in the reaction of $\ce{KMnO4}$ with $\ce{I-}$ in alkaline medium $\ce{IO3-}$ …

I am trying to figure out the shape of the iodate ion or $\ce{IO3^-}$. No matter how many times I draw it, I keep getting iodine in the centre, and 3 oxygen atoms surrounding it, 2 with single …

Sep 3, 2019 · Omitting the hydrogen ions would lead to $$\ce{IO3-(aq) + 5I-(aq) -> 3I2(aq) + 3O^2-}$$ but $\ce{O^2-}$ would not exist in water. So an alternative could be to write …

Dec 10, 2018 · convert it into ionic form = I2 + OH⁻ I⁻ + IO3⁻ oxidizing number of I went from 0 -1(I⁻) and +5 (IO3⁻) There's an "OH⁻" in the equation, which means the reaction is carried out in …

Feb 15, 2015 · 'm trying to figure out why the oxidation state of the iodate ion is +5. The iodine atom has 7 electrons in its outermost shell (comprised of s and p sub-shells). Two oxygen …

Mar 23, 2016 · I investigated the Arrhenius equation using the reaction between potassium iodate (containing the IO3- iodate ion) and sodium bisulfite (containing the HSO3- hydrogen sulfite …

Oct 18, 2020 · In acidic conditions, the reaction is finished here. But in basic solution, the iodine $\ce{I2}$ is transformed into iodide and iodate according to $$\ce{3I2 + 6 OH^- -> 5 I- + IO3^- …

Sep 19, 2016 · Iodate is $\ce{IO3-}$ thus periodate is $\ce{IO4-}$ Any additional hydrogen- prefixes are added as $\ce{H+}$ ions, thus they reduce the charge accordingly. This method …

Mar 14, 2016 · I advise you to attempt such a plot for the data where $\ce{[IO3-]}$ was varied. Regarding the systematic error, you should think about the fact that you determined average …

Nov 7, 2017 · $\ce{IO3- + 5I- +6H+ -> 3I2 + 3H2O}$ $\ce{3I2 + S2O3^-- -> 6I- + 3S4O6^--}$ The question. We were told that, during the standardization process, if the iodate-iodide solution is …