cot is a short way to write 'cotangent'. This is the reciprocal of the trigonometric function 'tangent' or tan (x). Therefore, cot (x) can be simplified to 1/tan...

In order to derive cot(x) 1 − sin(x), you need to apply the quotient rule first. The quotient rule states this: f '(x)g(x) − g'(x)f (x) g(x)2 Let's assume (1 −sin(x)) is g(x). Now, the f (x) that we will use for the quotient rule is not the equation they give us. It is the numerator, which is cot(x). So let's plug in our newly found f (x) and g(x), which is: d dxcot(x)(1 − sin(x)) − ...

-1 (cotx+cscx) (cotx−cscx) = (cot^2x-csc^2x) = (cos^2x/sin^2x - 1/sin^2x) = (cos^2x-1)/sin^2x =- (1-cos^2x)/sin^2x =-sin^2x/sin^2x =-1

Sep 26, 2016 · The derivative is distributive over addition and subtraction. Hence: dy dx = Dx[tanx] +Dx[cotx] Differentiating we get: dy dx = sec2x +(− csc2x) It is important to know the derivatives of the trigonometric functions.

Nov 3, 2015 · Verify trig expression. (cot x/sec^2 x) + (cot x/csc^2 x) = cot x First term of left side: ( (cos x/ (sin x))/ (1/ (cos^2 x))) = (cos^3 x)/ (sin x) (1) Second term of ...

Jul 1, 2016 · C is the correct answer. You need to put on a common denominator. This will be sinxcosx. =(sin^2x + cos^2x)/(sinxcosx) Applying the identity sin^2x + cos^2x = 1: =1/(sinxcosx) Now, recall that 1/sintheta = csctheta and 1/costheta = sectheta. =cscxsecx So, C is the answer that corresponds. Hopefully this helps!

Nov 12, 2016 · How do you verify sin x + cos x = cos x 1 − tan x + sin x 1 − cot x?

Apr 29, 2018 · The whole question is: Solve the equation for solutions over the interval [0, 2pi ) I know factoring is the first step.

Aug 28, 2016 · How do you simplify the expression sec x cot x − cot x cos x?

May 1, 2017 · cotx(secx +tanx) = cosx sinx (1 cosx + sinx cosx) = cosx sinx × 1 cosx + cosx sinx × sinx cosx = cosx sinx × 1 cosx + cosx sinx × sinx cosx = 1 sinx +1 = cscx + 1