x^{2}-x-6=0 -x+3\gt 2x+1 ; line\:(1,\:2),\:(3,\:1) f(x)=x^3 ; prove\:\tan^2(x)-\sin^2(x)=\tan^2(x)\sin^2(x) \frac{d}{dx}(\frac{3x+9}{2-x}) (\sin^2(\theta))' \sin(120)

Factor using the perfect square trinomial rule a2 + 2ab+b2 = (a+b)2 a 2 + 2 a b + b 2 = (a + b) 2, where a = r a = r and b = 1 b = 1. (r+1)2 (r + 1) 2. Free math problem solver answers your …

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r^{2}+r+\left(\frac{1}{2}\right)^{2}=-1+\left(\frac{1}{2}\right)^{2} Divide 1, the coefficient of the x term, by 2 to get \frac{1}{2}. Then add the square of \frac{1}{2} to both sides of the equation.

To write a polynomial in standard form, simplify and then arrange the terms in descending order. The standard form is 5r2 +20r+ 15 5 r 2 + 20 r + 15. Free math problem solver answers your …

Jun 12, 2022 · Experts consider the HER2+ breast cancer to be more aggressive than some other breast cancers. That means it may grow faster without treatment. The good news is that …

Mar 12, 2024 · HER2-positive breast cancer tends to be more aggressive than HER2-negative breast cancer. However, current therapies targeting the HER2 receptor are so effective that …

About 15% to 20% of breast tumors have higher levels of a protein known as HER2. These cancers are called HER2-positive breast cancers. Ask your cancer care team about your …