1/3 * 6/1 = 6/3 = 2/1 = 2 . Answer by Robee16(18) (Show Source): You can put this solution on YOUR ...

Notice how the term 2 is equal to 1*2 (where 1 is the value of n and 2 is the next number). Also, notice how 6=2*3 (where 2 is the value of n and 3 is the next number). Furthermore, take note that 12=3*4 (where 3 is the value of n and 4 is the next number) etc.... So ANY term in this sequence can be written as For instance, let's say that ...

Put down the y values in a row: 1 3 6 10 Find the first successive differences by subtracting neighboring numbers, and write their differences between and below them: 1 3 6 10 2 3 4 Find the second successive differences again by subtracting neighboring numbers, and writing their differences between and below them: 1 3 6 10 2 3 4 1 1 That took ...

The mean of the mean of the samples is the same as the sample mean, or 6. The sample means of n=2 are 1-3 1-6 1-7 1-9 1-10 3-1 3-6 3-7 3-9 3-10 etc. add all those means up and divide by their number, which is 30, to get the mean of the sampling distribution. With n=3 samples, you will get the same mean. The variability will be less the larger ...

Question 990549: Find the smallest possible set (i.e., the set with the least number of elements) that contains the given sets as subsets.

You can put this solution on YOUR website! 2x+1/3x=6 (2 1/3)X=6 (7/3)X=6 7X/3=6 CROSS MULTIPLY 7X=6*3 7X=18 X=18/7 ANS.

Lets start with a simple sequence of three random numbers between (1-10) from random.org I got 6,9,2,_ whats next, Ok back to random.org its came up with 5. So our problem is to come up with a formula f(n) that produces f(1)=6, f(2)=9, f(3)=2, and f(4)=5. f(1)=6 f(2)=9 f(3)=2 f(4)=5. Lets initially choose. f(n) = 6. f(1) = 6 check f(2) = 6 fail ...

8, 5, 4, 9, 1, 7, 6, 3, 2, 0. Hints: This series problems looks just like a normal series problem, but it is different. You must get "out of the box" and use your right brain to solve this one. Note, too, that the series ends with the last digit, as indicated by the period (.).

y = 2x - 3---if we start at x=0 none of the given y sequences match, but if we start with x=1, where 1 represents the first position in one of given y sequences, then we get a match.---if we use the x sequence 1,2,3,4,5 we get a perfect match with the given y sequence -1,1,3,5,7...---Solve and graph linear equations:

You can put this solution on YOUR website! For A U B we need the elements that occur in A or B so A U B = {2,3,5,6,7,9} Notice that 5 occurs in A and B but occurs only