Mar 24, 2016 · x= 0, pi, 2pi and (3pi)/2 cos^2 x = 1 - sin^2 x, hence the given equation would become 1-sin^2 x = 1+ sin x Or, " "sin^2 x +sin x=0 Or, " "sin x (sinx +1)=0 This give sin x=0 …

Oct 5, 2016 · x_1=0.25 and x_2 = 2.89 The easiest way to solve this type of problem is to plot the sin function and f(x) = 0.25 on one graph (link to this here) and look for the intersections. The …

Apr 11, 2018 · How do you solve for x in #3sin2x=cos2x# for the interval #0 ≤ x < 2π# See all questions in Solving Trigonometric Equations Impact of this question

Apr 30, 2015 · The value 0.7 is not one of the remarkable values of the function sinus, so: sin(x+40°)=0.7rArr x+40°=arcsin0.7+k360°rArr x=-40°+arcsin0.7+k360° and x+40°=180° …

Jun 30, 2015 · Solve f(x) = cos 2x + sin x + 1 = 0 f(x) = (1 - 2sin^2 x) + sin x + 1 = 0. Call sin x = t, we get: f(t) = -2t^2 + t + 2 = 0. D = d^2 = 1 + 16 = 17 -> d = +- sqrt17 sin x = t = 1/4 +- …

Dec 30, 2016 · Separate solving in 2 cases: a. #sin x = sqrt3/2# Trig table and unit circle give 2 solution arcs: #x = pi/3 and x = 2pi/3 #

Dec 7, 2016 · Factoring #sin(x)tan(x)sin(x)=0#. #sin(x) (tan(x)-1)=0# #rarr{:(sin(x)=0," or ",tan(x)=1),(x=kpi" " kin ZZ,, x=pi/4+kpi" " kin ZZ):}#

May 20, 2016 · For example, if sintheta=0, then 0*(whatever the other part becomes) will indeed =0. So, separately we will make the two parts =0. Starting with the left part, if sintheta=0, …

Jul 14, 2015 · Solutions are: x=pi*N x=-pi/6+2pi*N x=pi+pi/6+2pi*N where N - is any integer number. First of all, let's transform our equation into a one that depends only on sin(x). For …

Mar 27, 2016 · How do you find all values of x in the interval [0, 2pi] in the equation #2sin^2x - sinx - 1 = 0#? Trigonometry Trigonometric Identities and Equations Solving Trigonometric …