Mar 13, 2021 · In reaction of $\ce{KMnO4}$ with $\ce{I-}$ in acidic medium $\ce{I2}$ will be formed, whereas in the reaction of $\ce{KMnO4}$ with $\ce{I-}$ in alkaline medium $\ce{IO3-}$ …

I am trying to figure out the shape of the iodate ion or $\ce{IO3^-}$. No matter how many times I draw it, I keep getting iodine in the centre, and 3 oxygen atoms surrounding it, 2 with single …

Sep 3, 2019 · Omitting the hydrogen ions would lead to $$\ce{IO3-(aq) + 5I-(aq) -> 3I2(aq) + 3O^2-}$$ but $\ce{O^2-}$ would not exist in water. So an alternative could be to write …

Dec 10, 2018 · convert it into ionic form = I2 + OH⁻ I⁻ + IO3⁻ oxidizing number of I went from 0 -1(I⁻) and +5 (IO3⁻) There's an "OH⁻" in the equation, which means the reaction is carried out in …

Feb 15, 2015 · 'm trying to figure out why the oxidation state of the iodate ion is +5. The iodine atom has 7 electrons in its outermost shell (comprised of s and p sub-shells). Two oxygen …

Mar 14, 2016 · I advise you to attempt such a plot for the data where $\ce{[IO3-]}$ was varied. Regarding the systematic error, you should think about the fact that you determined average …

Nov 7, 2017 · $\ce{IO3- + 5I- +6H+ -> 3I2 + 3H2O}$ $\ce{3I2 + S2O3^-- -> 6I- + 3S4O6^--}$ The question. We were told that, during the standardization process, if the iodate-iodide solution is …

Sep 26, 2017 · experiment: $\pu{0.5 mL}~\ce{IO3-}$; time : $\pu{5.7 min}$ Looking at the rate law, the order is supposed to be one. I know that in order to conclude if the data matches the …

Mar 3, 2016 · $$\ce{5I- (aq) + 6H+ (aq) + IO3- (aq) -> 3I2 (aq) + 3H2O (l)}$$ The Arrhenius Equation can be rewritten as $$\ln k = \frac{-Ea}{{\rm R}T} + \ln A$$ Therefore, if ln k and 1/T …

Mar 28, 2021 · Let's start from the first such atom, iodine in the ion iodate $\ce{IO3-}$. We will build its own half-equation, step by step. We will build its own half-equation, step by step. It is …