Nov 7, 2015 · -27/8 A negative exponent is solved in two steps: first of all, consider the inverse of your fraction (i.e. : change numerator and denominator), and then consider the positive power of this inverse fraction. So, to compute your power, we make a first step: (-2/3)^-3 -> (-3/2)^3 And then apply the usual rule for the power of a fraction, i.e. the power of the numerator divided by …

Jun 25, 2017 · 1/9 "using the "color(blue)"laws of exponents" color(red)(bar(ul(|color(white)(2/2)color(black)(a^-mhArr1/a^m ; a^(m/n)hArr(root(n)(a))^mcolor(white)(2/2)|))) rArr27 ...

Mar 27, 2018 · First, we can rewrite the expression as: #7^(color(red)(2) xx color(blue)(1/3))# Next, we can use this rule of exponents to simplify the expression:

Nov 12, 2015 · 11/4. We start with 2 3/4. We now multiply the number on the left (2), by the denominator (4). We get a value of 8. We now add, to that value, the numerator (3). We get a value of 11. We now put that value over its denominator (4). …

Nov 3, 2017 · See a solution process below: We can use the point-slope formula for writing the equation for the line in the problem.

22/3 = 7 1/3 In order to know how to calculate this, first decide what it means... This is another way of writing 2 div 3/11 We could also write 2/1 div 3/11 to have both as fractions. Dividing by a fraction is the same as "X by the reciprocal" 2/1 xx11/3 = 22/3" "larr multiply straight across. But compare the two ways of writing this: (2/1)/(3/11) = (2xx11)/(1xx3)" "larr can you see a short ...

Mar 3, 2018 · #3-2xx(2+4)+5-(3/2)^3# we first look for #color(red)(P)#. There are two of them: #2+4# and a fraction #3/2#. We can't really do anything with the fraction for now, so let's do #2+4# first: #3-2xx(6)+5-(3/2)^3# Now we look for #color(blue)(E)#, which brings us back to that fraction: #3-2xx(6)+5-27/8#

Mar 29, 2017 · (2/3)^-2 = 9/4 = 2 1/4 (2/3)^-2 is a fraction with an exponent that would normally require multiplication of itself by the number of times indicated by the exponent.

Apr 2, 2017 · sum_(k=1)^n a_k = n - 1/2 + 1/2(1/3)^n The general term of a geometric series with initial term a and common ratio r can be written: a_k = a*r^(k-1) The sum to n terms is given (see footnote) by the formula: sum_(k=1)^n = (a(1-r^n))/(1-r) Note that: 2/3 = 1 - 1/3 8/9 = 1 - 1/9 26/27 = 1 - 1/27 So it seems that the general term of the given series is: a_k = 1 - 1/3^k We have: …

Feb 16, 2016 · #=x^(3/2)-:3/2# Instead of dividing by the fraction #"3/2"#, we can instead multiply by its reciprocal, #"2/3"#. #=x^(3/2)xx2/3# This can be written as #=(2x^(3/2))/3# This is a fine simplification. However, if you want to simplify the fractional exponent, we can use the rule which states that. #x^(a/b)=rootb(x^a)# Thus, the expression equals